Weight of Rail
Do you have ... the total weight of the rails used by the CPRR in initial construction?
posted from CPRR Discussion Group at 8:46 PM
Thursday, February 16, 2006
About Me
- Name: CPRR Discussion Group
Discussion Group – Central Pacific Railroad Photographic History Museum
Previous Posts
- Another patent question
- CP Oil Fuel
- 1870 Boxcars
- Transcontinental Railroad Historic Landmarks for o...
- Cost to build the Union Pacific Railroad
- Nevada Coal
- Traveling conditions/rail lines going to or near R...
- Cape Horn Slope
- Possible golden spike sighting
- B&MLRR
A log of messages discussing transcontinental railroad history and photography. Opinions are those of each person posting. PRIVACY.
SEARCH both the CPRR Museum and its CPRR Discussion Group:
To find replies, look for both comments linked to the original message and also for later messages.
SEARCH Problem
Anecdotes & Aphorisms
Favorite Camera Lenses
19th Century City Views
Railroad History Readings
Railroad Exhibits
Chinese Railroad Workers
Historical Accuracy
Discrimination Myths
Overestimating Mortality
Caution to Students
B&MLRR
Palace Hotel
Progress
Health Care Solution
No Robber Barons
Other Topics
How Not to Be Poor
How to be Rich
DONATE
"Dr. Ben's Kitchen!"
3 Comments:
Assuming a single track using 60 lb rail, and excluding yards and sidings:
690 mi x 2 rails x 60 lb/yard x 5280 ft/mi x 1/3 yard/ft = 145,728,000 lbs
145,728,000 lbs x 1/(2204.62262 lb/metric ton) = 66,101 metric tons
66,101 metric tons / 690 miles = 95.8 metric tons/mile
... For the entire transcontinental railroad (including the Union Pacific, i.e., 1776 miles total instead of 690 miles for the CPRR), it would be about 66,101 x 1776/690 = 170,138 metric tons of rail.
i read on a site that it took over 200,000 net tons of iron to complete the railroad
Post a Comment
<< Recent Messages